t=t^2+t+10

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Solution for t=t^2+t+10 equation: 



t=t^2+t+10

We move all terms to the left:

t-(t^2+t+10)=0

We get rid of parentheses

-t^2+t-t-10=0

We add all the numbers together, and all the variables

-1t^2-10=0

a = -1; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-1)·(-10)
Δ = -40
Delta is less than zero, so there is no solution for the equation

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